Question

ALGUIEN PUEDE RESOLVERLO PORFAVOR.​

Answer 1

Tip: las resistencias en serie se suman directamente pero en paralelo se suman inversamente:

a)

Rt = 10k + 10k + 10k

Rt = 30k

b)

1/Rt = 1/10k + 1/10k

1/Rt = 2/10k

1/Rt = 1/5k

Rt = 5k

c)

1/Rt = 1/60C + 1/30C + 1/20C

1/Rt = (1 + 2 + 3)/60C

1/Rt = 6/60C

1/Rt = 1/10C

Rt = 10C

d)

1/Rt1 = 1/60C + 1/80C

1/Rt1 = (4 + 3)/240C

1/Rt1 = 7/240C

Rt1= 240/7C

RT= Rt + 20C

RT = 240/7C + 20C

RT = (240 + 140)/7C

RT = 380/7C

RT = 54,29C

e)

Rt1 = 10C + 50C

Rt1 = 60C

1/Rt2 = 1/60C + 1/60C

1/Rt2 = 2/60C

1/Rt2 = 1/30C

Rt2 = 30C

Rt3 = 30C + 70C

Rt3 = 100C

1/RT = 1/100C + 1/100C

1/RT = 2/100C

1/RT = 1/50C

RT = 50C

f)

Rt1 = 300 + 200

Rt1 = 500

1/Rt2 = 1/500 + 1/000

1/Rt2 = (2 + 1) / 1000

1/Rt2 = 3/1000

Rt2 = 1000/3

RT = 1000/3 + 200 + 1000 + 2000

RT = 1000/3 + 3200

RT = (1000 + 9600)/3

RT = 10600/3

RT = 3533,33