Question

resolver la ecuación -2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}=-(y-4)

Answer 1

Respuesta:

-y          = --2y-3-{-4y+5+[-y+2-(3y-1)+2y-5]}-4

-y+2y    = -3-{-4y+5+[-y+2-(3y-1)+2y-5]}-4

-y+2y+7= -{-4y+5+[-y+2-(3y-1)+2y-5]}

-y+2y+7= 4y-5-[-y+2-(3y-1)+2y-5]

-y+2y+7= 4y-5+y-2+(3y-1)-2y+5

-y+2y+7= 4y-5+y-2+3y-1-2y+5

-y+2y+7= 6y-3

-y+2y-6y= -3-7

-5y          = -10  aqui miltiplicamos ambos lados por -1

5y           = 10

y             = 10/5    =====>     y=2

Explicación paso a paso: