Question

HALLAR "Y"
x² + y²=1

Answer 1

$x^2+y^2=1\\ \\ y^2=1-x^2\\ \\ \sqrt{y^2}=\sqrt{1-x^2}\\ \\ |y|=\sqrt{1-x^2}\\ \\ \\ \boxed{y=\pm\sqrt{1-x^2}}$