Question

hallar "K" sabiendo que MCD (210k, 300k, 420k) = 1200

Answer 1

$\mbox{MCD}(210k,300k,420k)=1200\\ \\ 10k\cdot \mbox{MCD}(21,30,42)=1200\\ \\ 10k\cdot 3=1200\\ \\ \boxed{k=40}$

Answer 2

Respuesta:

$MCD (210k, 300k, 420k) = 1200$

$10k . MCD (210, 300, 420) = 1200$

$10K . 3 = 1200$

$K = 40$