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Hola Nathalia
![\not 8( 2-x)^{2} =\not2( 8-x)^{2} ---\ \textgreater \ simplificando~tenemos: \\ \\ 4( 2-x)^{2} =( 8-x)^{2} ---\ \textgreater \ por~propiedad[( a-b)^{2} = a^{2} -2ab+ b^{2} ] \\ \\ 4[4-4x+ x^{2} ]=64-16x+ x^{2} \\ \\ 16-\not16x+4 x^{2} =64-\not16x+ x^{2} ~--\ \textgreater \ simplificar \\ \\ 16+4 x^{2} =64+ x^{2} \\ \\ 4 x^{2} - x^{2} =64-16 \\ \\ 3 x^{2} =48 \\ \\ x^{2} = \frac{48}{3} \not 8( 2-x)^{2} =\not2( 8-x)^{2} ---\ \textgreater \ simplificando~tenemos: \\ \\ 4( 2-x)^{2} =( 8-x)^{2} ---\ \textgreater \ por~propiedad[( a-b)^{2} = a^{2} -2ab+ b^{2} ] \\ \\ 4[4-4x+ x^{2} ]=64-16x+ x^{2} \\ \\ 16-\not16x+4 x^{2} =64-\not16x+ x^{2} ~--\ \textgreater \ simplificar \\ \\ 16+4 x^{2} =64+ x^{2} \\ \\ 4 x^{2} - x^{2} =64-16 \\ \\ 3 x^{2} =48 \\ \\ x^{2} = \frac{48}{3}](https://tex.z-dn.net/?f=%5Cnot+8%28+2-x%29%5E%7B2%7D+%3D%5Cnot2%28+8-x%29%5E%7B2%7D+---%5C+%5Ctextgreater+%5C+simplificando%7Etenemos%3A+%5C%5C++%5C%5C+4%28+2-x%29%5E%7B2%7D+%3D%28+8-x%29%5E%7B2%7D+---%5C+%5Ctextgreater+%5C+por%7Epropiedad%5B%28+a-b%29%5E%7B2%7D+%3D+a%5E%7B2%7D+-2ab%2B+b%5E%7B2%7D+%5D+%5C%5C++%5C%5C+4%5B4-4x%2B+x%5E%7B2%7D+%5D%3D64-16x%2B+x%5E%7B2%7D++%5C%5C++%5C%5C+16-%5Cnot16x%2B4+x%5E%7B2%7D+%3D64-%5Cnot16x%2B+x%5E%7B2%7D+%7E--%5C+%5Ctextgreater+%5C+simplificar+%5C%5C++%5C%5C+16%2B4+x%5E%7B2%7D+%3D64%2B+x%5E%7B2%7D++%5C%5C++%5C%5C+4+x%5E%7B2%7D+-+x%5E%7B2%7D+%3D64-16+%5C%5C++%5C%5C+3+x%5E%7B2%7D+%3D48+%5C%5C++%5C%5C++x%5E%7B2%7D+%3D+%5Cfrac%7B48%7D%7B3%7D+)
![x^{2} =16 \\ \\ x=+- \sqrt{16} \\ \\ x=+-4 \\ \\ \boxed{\boxed{ C.S=\{+4,-4\}}} x^{2} =16 \\ \\ x=+- \sqrt{16} \\ \\ x=+-4 \\ \\ \boxed{\boxed{ C.S=\{+4,-4\}}}](https://tex.z-dn.net/?f=+x%5E%7B2%7D+%3D16+%5C%5C++%5C%5C+x%3D%2B-+%5Csqrt%7B16%7D++%5C%5C++%5C%5C+x%3D%2B-4+%5C%5C++%5C%5C+%5Cboxed%7B%5Cboxed%7B+C.S%3D%5C%7B%2B4%2C-4%5C%7D%7D%7D)
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Espero te sirva, saludos!!
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Espero te sirva, saludos!!
nathalianico:
muchisisisisisimas gracias
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