• Asignatura: Matemáticas
  • Autor: lupevillagra91
  • hace 8 años

Esos 3 tambien por favor

Adjuntos:

Respuestas

Respuesta dada por: huamanmalca
0

Explicación paso a paso:

c)

(u+2) / (3.u-1) + 1 = (6-u) / (u+1)

(u + 2 + 3.u - 1) / (3.u-1) = (6-u) / (u+1)

(4.u + 1) . ( u+1 ) = (6-u) . (3.u-1)

4.u^2 + 4.u + u + 1 = 18.u - 6 - 3.u^2 + u

7.u^2 - 14.u + 7 = 0

7.u - 7

1.u - 1

(7.u - 7) . ( 1.u- 1) = 0

7.u - 7=0 y 1.u-1 =0

u=1 y u =1

Entonces el valor de u es 1.

e)

x^2 = 5.x - 6

x^2 - 5.x + 6 = 0

x -3

x -2

(x-3) . (x-2) = 0

x-3 = 0 y x-2=0

x =3 y x =2

Entonces los valores de x son 3 y 2

i)

(3) / (x-1) - (5.x) / (x+2) = 1/4

[ 3. (x+2) - 5.x. (x-1) ] / (x-1).(x+2) = 1/4

3. (x+2) - 5.x. (x-1) = (x-1) . (x+2) / 4

3.x + 6 - 5.x^2 + 5.x = (x^2 +2.x - x - 2) / 4

4. (-5.x^2 +8.x +6) = (x^2 + x - 2)

-20.x^2 + 32.x + 24 = x^2 + x - 2

21.x^2 - 31.x - 26 = 0

Aplicamps formula cuadratica:

x1 = [b + (b^2 - 4.a.c)^ (1/2) ] / (2.a)

x1 = [-31 + ((-31)^2 - 4.(21).(-26))^ (1/2) ] / (2.(21))

x1 = [-31 + (961 + 2184)^(1/2) ] / 42

x1 = [-31 + (961 + 2184)^(1/2) ] / 42

x1 = (-31 + 56, 08) / 42

x1 = -0,597

Para x2:

x2 = [b - (b^2 - 4.a.c)^ (1/2) ] / (2.a)

x2 = [-31 - ((-31)^2 - 4.(21).(-26))^ (1/2) ] / (2.(21))

x2 = [-31 - (961 + 2184)^(1/2) ] / 42

x2 = [-31 - (961 + 2184)^(1/2) ] / 42

x2 = (-31 - 56, 08) / 42

x2 = 2,073

Preguntas similares