Question

resuelve cada sistema de ecuaciones por la regla de cramer .
b. (3 a - 2 b = 13
2 a + 4 b = 3

Answer 1

$\Delta = \left|\begin{matrix}3&-2\\2&4\end{matrix}\right| = 16 \\ \\ \Delta_a = \left|\begin{matrix}13&-2\\3&4\end{matrix}\right| = 58 \\ \\ \Delta_b = \left|\begin{matrix}3&13\\2&3\end{matrix}\right| = -17 \\ \\ \\ \\ \displaystyle a =\frac{\Delta_a}{\Delta}=\frac{58}{16}\\ \\ b=\frac{\Delta_b}{\Delta}=-\frac{17}{16}$