Question

La masa molecular del los compuesto H202, H2S04 , HN03 . KMn03 . CH3CH20H. CH4. Na0H. C3H8. H3P04. HI03. H2SO3. H2C2O4

Answer 1

Respuesta:

espero poder ayudarte

Explicación:

H202= 34,0147 g/mol

H2A04= 98,079 g/mol

HN03= 63,01 g/mol

KMn03= 142.033 g/mol

CH3CH20H= 48.21 g/mol

CH4= 16.04 g/mol

Na0H= 40 g/mol

C3H8= 44.09 g/mol

H3P04= 97.994 g/mol

HI03= 175.9 g/mol

H2SO3= 82.08 g/mol

H2C2O4= 90.03

Answer 2

Respuesta:

1.-H2O2 = 34,0147 g/mol

2.-H2SO4 = 98,079 g/mol

3.-HNO3 = 63,01 g/mol

4.-KMnO3 = 158,034 g/mol

5.-CH3CH20H = 46,07 g/mol

6.-CH4 = 16,04 g/mol

7.-NaOH = 39,997 g/mol

8.-C3H8 = 44,1 g/mol

9.-H3PO4 = 97,994 g/mol

10.-HIO3 = 175,91 g/mol

11.-H2SO3 = 82,07 g/mol

12.-H2C2O4 = 90,03 g/mol

De nada :D