Respuestas
Respuesta:36+121c2-132c
Final result :
(11c - 6)2
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(36 + 112c2) - 132c
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 121c2-132c+36
The first term is, 121c2 its coefficient is 121 .
The middle term is, -132c its coefficient is -132 .
The last term, "the constant", is +36
Step-1 : Multiply the coefficient of the first term by the constant 121 • 36 = 4356
Step-2 : Find two factors of 4356 whose sum equals the coefficient of the middle term, which is -132 .
-4356 + -1 = -4357
-2178 + -2 = -2180
-1452 + -3 = -1455
-1089 + -4 = -1093
-726 + -6 = -732
-484 + -9 = -493
-396 + -11 = -407
-363 + -12 = -375
-242 + -18 = -260
-198 + -22 = -220
-132 + -33 = -165
-121 + -36 = -157
-99 + -44 = -143
-66 + -66 = -132 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -66 and -66
121c2 - 66c - 66c - 36
Step-4 : Add up the first 2 terms, pulling out like factors :
11c • (11c-6)
Add up the last 2 terms, pulling out common factors :
6 • (11c-6)
Step-5 : Add up the four terms of step 4 :
(11c-6) • (11c-6)
Which is the desired factorization
Multiplying Exponential Expressions :
2.2 Multiply (11c-6) by (11c-6)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (11c-6) and the exponents are :
1 , as (11c-6) is the same number as (11c-6)1
and 1 , as (11c-6) is the same number as (11c-6)1
The product is therefore, (11c-6)(1+1) = (11c-6)2
Final result :
(11c - 6)2
Explicación: