Question

calcule la normalidad de 60 gr de Na2CO3 en 200 ml de solución​

Answer 1

N = ?

m = 60g

V = 200 mL = 0.2L

Na2CO3

O = 16*3 = 48

C = 12*1 = 12

Na = 23*2 = 46

PM = 318

M = (m / PM) / V

60g / 318 = 0.18 / 0.94

M = 0.94

N = (eq) (M)

N = (2) (0.94)

N = 1.88