Question

si:tgx+cotgx=5,halar
E=tg2x+ctg2x

Answer 1

$\tan x + \cot x = 5\\ (\tan x + \cot x)^2 = 25\\ \tan^2 x + 2\tan x \cdot \cot x + \cot^2 x = 25\\ \tan^2 x + 2 + \cot^2 x = 25\\ \tan^2 x + \cot^2 x = 23$