Question

((3/4-1/2)÷4/3+1/1)÷(-3/4+1/3)×3/2=-171/40
con procedimiento

Answer 1

$(( \frac{3}{4}- \frac{1}{2}): \frac{4}{3}+ \frac{1}{1}):(- \frac{3}{4}+ \frac{1}{3})* \frac{3}{2}=- \frac{171}{40} \\ \\ (( \frac{3-2}{4}): \frac{4}{3}+1):( \frac{-3*3+1*4}{12})* \frac{3}{2}= \\ \\ ( \frac{1}{4}: \frac{4}{3}+1):( \frac{-5}{12})* \frac{3}{2}= \\ \\ ( \frac{3}{16}+1):( \frac{-5*3}{12*2})}= \\ \\ ( \frac{3}{16}+ \frac{16}{16}):( \frac{-5*3}{12*2})}= \frac{19}{16}:- \frac{5}{8}=- \frac{152}{80} = \boxed{- \frac{19}{10}}$

Espero que te sirva, salu2!!!!