Question

2y -3x/4 +5/2=0 x+y/2 +1=0

Answer 1

Respuesta:

Bueno, no entendi muy bien pero te dejo 2 soluciones :)

• Forma 1 :

Resolvemos :

$\frac{2y-3x}{4}+\frac{5}{2}=0\\ \\\frac{2y-3x}{4}=-\frac{5}{2}\\\\2y-3x=-(\frac{5}{2}).4\\\\2y-3x=-10$       ;       $\frac{x+y}{2}+1=0\\\\\frac{x+y}{2}=-1\\\\x+y=-2$

Sistema De Ecuaciones :

-3x + 2y = -10

x + y = -2 ; Multiplicamos por 3 a ( x + y = -2 )

Nuestro Sist. quedaria de la sigte. manera :

-3x + 2y = -10

( x + y = -2 ) 3

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-3x + 2y = -10

3x + 3y = -6

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(-3x+3x) + (2y+3y) = -16

0 + 5y = -16

y= -16/5

Reemplazamos para hallar x :

x + y = -2

x + (-16/5) = -2

x  - (16/5) = -2

x = -2 + (16/5)

x = -10/5 + 16/5

x= 6/5

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• Forma 2 :

Si $2y -3x/4 +5/2=0$  y  $x+y/2 +1=0$ , Entonces podemos decir que :

$2y -\frac{3x}{4} +5/2=x+\frac{y}{2} +1\\\\2y-\frac{y}{2}=x+\frac{3x}{4} +1-5/2\\\\\frac{4y}{2} -\frac{y}{2}=\frac{4x}{4} +\frac{3x}{4}+ \frac{2}{2} -\frac{5}{2} \\\\\frac{3y}{2} =\frac{7x}{4} -\frac{3}{2} \\\\\frac{6y}{4} =\frac{7x}{4} -\frac{6}{4}\\\\\frac{6y}{4}+\frac{6}{4}=\frac{7x}{4}\\\\6y+6=7x\\\\x=\frac{6y+6}{7}$

Reemplazamos en la segunda ecuacion :

$x+y/2 +1=0\\\\\frac{6y+6}{7}+\frac{y}{2}+1=0\\ \\\frac{2(6y+6)+7y}{7.2}+\frac{14}{14}=0\\ \\\frac{12y+12+7y}{14}+\frac{14}{14}=0\\\\\frac{19y+12}{14}+\frac{14}{14}=0\\ \\\frac{19y+12+14}{14}=0\\\\\frac{19y+26}{14}=0\\\\19y+26=0\\\\19y=-26\\\\y=\frac{-26}{19}$

Hallamos x :

$x+\frac{y}{2} +1=0\\\\x+\frac{\frac{-26}{19} }{2}+1=0\\ \\x+\frac{-26}{38}+1=0\\ \\x+\frac{-26}{38}+\frac{38}{38}=0\\ \\x+\frac{-26+38}{38}=0\\\\ x+\frac{12}{38}=0\\\\ x+\frac{6}{19}=0\\\\ x=-\frac{6}{19}$