• Asignatura: Matemáticas
  • Autor: Romina1212232
  • hace 8 años


POR FAVOR ES PARA MAÑAANA

Adjuntos:

Respuestas

Respuesta dada por: msanpedrojorgep9vtr3
1

1)

a)

 = ( - 12) \times (3) +  \frac{18}{ \frac{ - 12}{6}  + 8}  \\  =  - 36 +  \frac{18}{ - 2 + 8}  \\  =  - 36 +  \frac{18}{6}  \\   =  - 36 + 3 \\  =  - 33

b)

 =  \sqrt{ - 2 + 6 - (2.3 + 2 {}^{2}) {}^{0}   - ( - 1) {}^{13}  }  \\   =  \sqrt{4 - (1) - ( - 1)}  \\  =   \sqrt{4 - 1 + 1}  \\  =  \sqrt{4}  \\  =  \frac{ + }{} 2

c)

 =  - 5 +   \frac{ {3}^{5} }{3 {}^{2} }  - 5 \times ( - 3) +  \sqrt[3]{ - 27}  \\  =  - 5 +  {3}^{5 - 2}  + 15 + ( - 3) \\  =  - 5 +  {3}^{3}  + 15 - 3 \\  =  - 5 + 27 + 12 = \\  = 34

d)

 =  \frac{(17 - 15) {}^{3}  + (7 - 12) {}^{2} }{(6 - 7)(12 - 23)}  \\  =  \frac{ {(2)}^{3}  +  {( - 5)}^{2} }{( - 1) \times ( - 11)}  \\  =  \frac{8 + 25}{11}  \\  =  \frac{33}{11}  \\  = 3

2)

a)

 = 5 {}^{4}  \times 5 {}^{8}  \\  =  {5}^{8 + 4}  \\  =  {5}^{12}

b)

 = 12 {}^{6}  \times 12 {}^{3}  \\  =  {12}^{6 + 3}  \\  = 12 {}^{9}

c)

 =  {4}^{3}  \times  {4}^{ 3}  \times  {4}^{1}   \\  =  {4}^{3 + 3 + 1}  \\  = 4 {}^{7}

d)

 = 7 {}^{3}  \times 7 {}^{2}  \times  {7}^{4}  \\  = 7 {}^{3 + 2 + 4}  \\  =  {7}^{9}

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