Question

sea f(x)= x^2-2x-3. Calcular f(-3); f(2-raiz de 2) y f(5)

Answer 1

Respuesta:

f(-3) = 12

f(5) = 12

f($2-$$\sqrt{2}$) = $-1-2\sqrt{2}$

Explicación:

f(x) = $x^2-2x-3$ = $(x-3)(x+1)$

f(-3) = (-3-3)(-3+1) = (-6)(-2) = 12

f(5) = (5-3)(5+1) = (2)(6) = 12

f($2-\sqrt{2}$) = ($-1-\sqrt{2}$)($3-\sqrt{2}$) = $-3+\sqrt{2} -3\sqrt{2} +2$ = $-1-2\sqrt{2}$