De las funciones dadas obtener f + g, f – g, f * g, f/g, (f o g) (x); (g o f) (x); suma, resta, multiplicación, división y función compuesta de las siguientes funciones
Sea f(x)=2x/(x-3) y g(x)=x^2
Sea f(x)=√(5&x^4 ) y g(x)=x^2/log_22x
Sea f(x)=log〖(x+2)〗 y g(x)=1-x^4
Sea f(x)=√2x y g(x)=〖(ln3x)〗^2
Sea f(x)=x+5 y g(x)=2/lnx
Sea f(x)=x^2+5x-2 y g(x)=2-3x
Sea f(x)=〖(3x-4)〗^2y g(x)=6+x
Sea f(x)=√(5&x^4 )/x y g(x)=(2-x^2)/4
me pueden ayudar lo nesesito para hoy
Respuestas
Los resultados de las operaciones : f+g , f-g , f*g , f/g , ( fog)(x) , (gof)(x) son :
f(x)=2x/(x-3); g(x)=x^2
f + g = 2x/(x-3) + x²= (2x+x³-3x²)/(x-3)
f - g= 2x/(x-3) - x²= (2x-x³+3x²)/(x-3)
f*g= 2x/(x-3) *x²= (2x³)/(x-3)
f/g= 2x/(x-3) /x²=2/(x²-3x)
(fog)(x) = 2x²/(x²-3 )
(gof)(x) = 4x²/(x-3)²
f(x)=√(5x^4 ) ; g(x)=x^2/log₂2x
f +g = √(5x^4 )+x^2/log₂2x
f -g = √(5x^4 )- x^2/log₂2x
f*g = √(5x^4 )*x^2/log₂2x = √5x^4/log₂2x
f/g= √(5x^4 )/x^2/log₂2x= √5*log₂2x/x²
(fog)(x) = √(5*(x^2/log₂2x)^4 = √5* x^4/(log₂2x)^2
(gof)(x)= (√(5x^4 ) ^2/ log₂ 2*√(5x^4 )= 5x^4/log₂(2√5 x^2)
f(x)=log〖(x+2)〗 ; g(x)=1-x^4
f+ g = log〖(x+2)〗 + 1-x^4
f -g = log〖(x+2)〗 - 1-x^4
f*g = log〖(x+2)〗 *( 1-x^4)
f/g = log〖(x+2)〗/(1-x^4)
(fog)(x) = log 〖(1-x^4+2)〗= log 〖(3-x^4)〗
(gof)(x) = 1 - ( log〖(x+2)〗)^4
f(x)=√2x ; g(x)=〖(ln3x)〗^2
f + g = √2x + 〖(ln3x)〗^2
f - g = √2x - 〖(ln3x)〗^2
f*g = √2x*〖(ln3x)〗^2
f/g = √2x/〖(ln3x)〗^2
(fog)(x) = √2〖(ln3x)〗^2
(gof)(x) = 〖(ln3√2x)〗^2
f(x)=x+5 ; g(x)=2/lnx
f + g= x+5 + 2/lnx
f - g = x+5 - 2/lnx
f*g = 2*(x+5)/lnx
f/g= ( x+5)*lnx/2
(fog)(x) = 2/lnx +5 = ( 2 +5*lnx)/lnx
(gof)(x) = 2/ln(x+5)