Question

El lado de un rombo mide 12,5 cm y una de sus diagonales mide 15 cm. ¿Cuánto
mide la otra diagonal?

Answer 1

Respuesta:

D₂= 15cm

Explicación paso a paso:

D₁=15cm

D₂= ?

L = 12.5cm²

Aplicando el teorema de pitagoras:

$L^{2} = (\frac{D_{1} }{2} )^{2} +(\frac{D_{2} }{2} )^{2} \\(12.5)^{2} =(\frac{15}{2})^{2} +(\frac{D_{2} }{2})^{2} \\(\frac{D_{2} }{2})^{2} = (12.5)^{2} -(\frac{15}{2})^{2}\\\frac{D_{2} }{4}^{2} = (12.5)^{2} -\frac{225}{4} \\\frac{D_{2} }{4}^{2} = 56.25\\(D_{2})^{2} =56.25*4\\D_{2} = \sqrt{225} \\D_{2} = 15 cm$