Question

metodo de sustitución 4x+3y=11, 5x+2y=8

Answer 1

SOLUCIÓN

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                       $Despejaremos\:"x"\:de\:la\:primera\:ecuaci\'on\\\\4x+3y=11\\\\\\4x=11-3y\\\\\\x=\dfrac{11-3y}{4}\\\\\\Reemplazamos\:x\:en\:la\:segunda\:ecuaci\'on\\\\\\5x+2y=8\\\\\\(5)\left(\dfrac{11-3y}{4}\right)+2y=8\\\\\\\dfrac{(5)(11-3y)+[(4)(2y)]}{4}=8\\\\\\(55-15y)+(8y)=(8)(4)\\\\\\55-7y=32\\\\\\-7y=-23\\\\\\y=\dfrac{-23}{-7}\\\\\\\boxed{\boldsymbol{y=3.28571}}$

                      $Reemplazamos\:"y"\:en\:"x"\\\\\\x=\dfrac{11-3y}{4}\\\\\\x=\dfrac{11-3(3.28571)}{4}\\\\\\x=\dfrac{11-9.85714}{4}\\\\\\x=\dfrac{1.14286}{4}\\\\\\\boxed{\boldsymbol{x=0.285714}}$