Question

Alguien sabe este problema de polinomio??? ​

Answer 1

$\dfrac{3\cdot 5\cdot7\cdot9\cdots (2n+1)}{1\cdot3\cdot5\cdot7\cdot9\cdots(2n-1)}=145\\ \\ \\2n+1=145\\ \\\boxed{n=72}$

Answer 2

Respuesta:

72

Explicación paso a paso:

*datos:

P(x)=(x+1)/(x-1)

P(2)P(4)P(6).....P(2n)=145

*evaluando:

P(2)=(2+1)/(2-1) =3/1

P(4)=(4+1)/(4-1) =5/3

P(6)=(6+1)/(6-1) =7/5

P(8)=(8+1)/(8-1) =9/7

:

:

P(2n)=(2n+1)/(2n-1)

*resolviendo:

P(2)P(4)P(6)P(8).....P(2n)=145

(3/1)(5/3)(7/5)(9/7).....[(2n+1)/(2n-1)]=145

simplificando

(2n+1)/1=145

2n+1=145

2n=145-1

2n=144

n=144/2

n=72