Question

Hallar dos números consecutivos sabiendo que los tres octavos del menor, aumentado en uno es equivalente a los dos quintos del mayor

Answer 1

X=MENOR

X+1=MAYOR

$\frac{3}{8} (x)+1=\frac{2}{5} (x+1)\\\\\frac{3}{8}x+1=\frac{2}{5}x+\frac{2}{5}\\\\\frac{3}{8}x=-\frac{3}{5}+\frac{2}{5}x\\\\\frac{3}{8}x-\frac{2}{5}x=-\frac{3}{5}+\frac{2}{5}x-\frac{2}{5}x\\\\-\frac{1}{40}x=-\frac{3}{5}\\\\\left(-\frac{1}{40}x\right)\left(-40\right)=\left(-\frac{3}{5}\right)\left(-40\right)\\\\x=24$