Question

Hallar n . (n+2/n!)=3!/3

Answer 1

Explicación paso a paso:

n(n+2/n!)=3!/3

n[(n.n!+2)/(n-1)!.n]=(2!.3)/3

(n.n!+2)/(n-1)!=2!

n.(n-1)!.n+2=2(n-1)!

(n^2)+2=[2(n-1)!]/(n-1)!

(n^2)+2=2

(n^2)=2-2

n^2=0

n=(raiz cuadrada) de 0

n=0