Question

Por favor ayudenme con 5 ejemplos de la propiedad distributiba

Answer 1

Respuesta:

(4+2)3 = (4 x 3) + (2 x 3) = 12 + 6 = 18

(6 + 9)10 = (6 x 10) + (9 x 10) = 60 + 90= 150

5x(3 – 4) = ((5 x)(3)) + ((5x)(–4)) = 15x – 20x = –5x

(3 + 9)9 = (3 X 9) + (9 X 9) = 27 + 81 = 108

2(5 + 7) = (2 X 5) + (2 X 7) = 24

(8+5)(5+7) = (8X5)+(8X7)+(5X5)+(5X7) = 40+56+25+35 = 156

(11–3)(8–3) = (11X8)+(11X–3)+(–3X8)+(–3X–3) = 88–33–24+9=40

(a+2b+c)3 = (3a)+(6b)+(3c) = 3ª+6b+3c

(a+b)(a–b) = [(a)(a)]+[(a)(–b)]+[(b)(a)]+[(b)(–b)] = [a2]+[–ab]+[ab]+[–b2] = a2–b2

(a–b–c)(a2+3ab+4b2+c) = (a3) + (3a2b) + (4ab2) + (ac) + (–a2b) + (–3ab2) + (–4b3) + (–bc) + (–a2c) + (–3abc) + (–4 b2c) + (–c2) = a3 + 3a2b + 4ab2 + ac – a2b – 3ab2 – 4b3 – bc – a2c – 3abc – 4b2c – c2 = a3 + 2a2b + ab2 – 4b3 + ac  – bc – 3abc – a2c – 4b2c – c2

Explicación paso a paso: