Question

Ayúdame porfavor es para mañana te doy 20 pts

Answer 1

Respuesta:

*$\frac{5969}{210}$

*$\frac{44}{35}$

*$\frac{203}{2655}$

*$\frac{1827}{4}$

Explicación paso a paso:

*$(6\frac{2}{5} +10\frac{1}{3} +12\frac{11}{7} )-(\frac{4}{3}+\frac{x}{y} \frac{x}{y} +\frac{5}{6} +1) = (\frac{12}{5}+ \frac{31}{3} +\frac{132}{7})-\frac{19}{6} =\frac{3317}{105}-\frac{19}{6} =\frac{5969}{210}$

*$(\frac{4}{3} +\frac{2}{5} +\frac{1}{6} )-(\frac{4}{7} +\frac{1}{14} ) = \frac{19}{10} -\frac{9}{14} = \frac{44}{35}$

* $\frac{3}{18}(\frac{1}{3} +\frac{9}{4} +\frac{8}{10} ) /(3\frac{1}{4} +4\frac{2}{16} )= \frac{1}{6} x\frac{203}{60} / ((3+4)+(\frac{1}{4} +\frac{2}{16}) = \frac{1}{6}x\frac{203}{60} /(7+\frac{3}{8})=\frac{1}{6} x\frac{203}{60} /7\frac{3}{8} = \frac{1}{6} x\frac{203}{60} /\frac{59}{8} =\frac{1}{6} x\frac{203}{60} x\frac{8}{59} =\frac{1}{3} x\frac{203}{60} x\frac{1}{59} =\frac{203}{2655}$

*$(4\frac{1}{5} +\frac{7}{3} )x(7-\frac{4}{7} )x(10\frac{1}{2} +\frac{3}{8} )= (\frac{21}{5} +\frac{7}{3} )x\frac{45}{7} x(\frac{21}{2} +\frac{3}{8} )= \frac{98}{15} x\frac{45}{7} x\frac{87}{7} = 14x3x\frac{87}{8}= 7x3x\frac{87}{4} = \frac{1827}{4}$