A cubic meter of soil in its natural state weighs 17.75 kn; after being dried it weighs 15.08 kn. the specific gravity of the solids is 2.70. determine the wáter content, void ratio, porosity and degree of saturation for the soil as existed in its natural state
Respuestas
the wáter content, void ratio, porosity and degree of saturation for the soil as existed in its natural state are :
w= 17.7% ; e = 0.756 ; n = 0.4 ; Sr = 0.716
Given :
W = 17.75 KN → Wd = 15.08 KN (when dried)
Gs= 2.70
V = 1 m³
w =? e =? n =? Sr =?
Volumen masa
Air ( 1 -Sr)*e o
water e Sr*e wGsρw
Solid 1 Gsρw
a) w = Mw/Ms
w = ( 17.75 - 15 .08 ) /15.08 = 0.177→ w= 17.7%
γ = Gs*(1+w) γw/( 1+e) = W/V = 17.75/1 = 17.75 KN/m³
17.75 = 2.70* ( 1 + 0.177 )*9.81/(1+e)
de donde:
void ratio e = 0.756
porosity : n = Vv/V = e/(1+e)
n= 0.4
Sr = W*Gs/e = 0.177*2.70 /0.667
Sr = 0.716