Question

AYUDA POR FAVOR

en un triangulo ABC, recto en B, se sabe que : tgA = 2,4

Calcular : J= csc C + ctg C

Answer 1

Explicación paso a paso:

$\tan(A) = 2.4 \\ \tan(A) = \frac{24}{10} \\ \tan(A) = \frac{12}{5}$

》Sabiendo los catetos, calculamos la hipotenusa:

${(hip)}^{2} = {12}^{2} + {5}^{2} \\ {(hip)}^{2} = 144 + 25 \\ {(hip)}^{2} = 169 \\ hip = \sqrt{169} \\ hip = 13$

》Ahora calculamos "J":

$J= \csc (C) + ctg (C) \\ J=</strong><strong>\frac{</strong><strong>13</strong><strong>}{5}</strong><strong>+</strong><strong> \</strong><strong>frac</strong><strong>{</strong><strong>12</strong><strong>}{5} </strong><strong>\</strong><strong>\</strong><strong>J</strong><strong> </strong><strong>=</strong><strong>\</strong><strong>frac</strong><strong> </strong><strong>{</strong><strong>13</strong><strong>+</strong><strong>12</strong><strong>}</strong><strong>{</strong><strong>5</strong><strong>}</strong><strong>\</strong><strong>\</strong><strong>J</strong><strong>=</strong><strong>\</strong><strong>frac</strong><strong> </strong><strong>{</strong><strong>25</strong><strong>}</strong><strong>{</strong><strong>5</strong><strong>}</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> </strong><strong>J</strong><strong>= 5$

》Respuesta:

J = 5