Question

((2m+3)(2m-4)+1=4(m+1)^{2}+3

Answer 1

Explicación paso a paso:

$(4m + 3)(2m - 4) + 1 = 4(m + 1) ^{2} + 3 \\ 4 {m}^{2} - 8m + 6m - 12 + 1 = 4( {m}^{2} + 2m + 1) + 3 \\ 4 {m}^{2} - 2m - 11 = 4 {m}^{2} + 8m + 4 + 3 \\ 4 {m}^{2} - 2m - 11 = 4 {m}^{2} + 8m + 7 \\ 4 {m}^{2} - 4 {m}^{2} - 2m - 8m = 7 + 11 \\ - 10m = 18 \\ m = - \frac{18}{10} \\ \\ m = - \frac{9}{5}$