Question

ARITMÉTICA-MÚLTIPLOS

Answer 1

(1)  (a+b+c+d + e) + (e - d + c -b + a) = 2c mod 8

2a + 2c + 2e = 2c mod 8

2(a + e) = 0 mod 8

a + e = 4

(2) (a,e) = {13,22,31} ---> 5a+e ={8, 12, 16} --->  25- (5a + e) = {17, 13, 9 }  ---base 5--- {32(5), 23(5), 14(5)}

C.A max = 32(5)