Question

Me ayudan por favor amigos es urgente.. ​

Answer 1

Respuesta:

$2^{x^{2}-1 } =8\\2^{x^{2}-1 }=2^{3} \\x^2 -1=3\\\x^2=4\\x=2$

$3^x.9^x=9^3\\3^x.3^{2x}=3^{2(3)}\\3^{3x} =3^6\\3x=6\\x=2$

$2^{5-x^2}=\frac{1}{16}  \\2^{5-x^2}=2^{-4} \\5-x^2=-4\\-x^2=-9\\x^2=9\\x=3$

$5^{x+3}=\sqrt{125}  \\5^{x+3}=\sqrt{5^3} \\5^{x+3}=5^{\frac{3}{2} }\\x+3=\frac{3}{2}\\ x=\frac{3}{2} -3\\x=-\frac{3}{2}$

$3^{x+1} +3^x+3^{x-1}=39\\3^x(3+1+\frac{1}{3})=39\\ 3^x(\frac{13}{3} )=39\\3^x=39(\frac{3}{13})\\ 3^x=9\\x=2$

$2^{x+1} +2^x+2^{x-1}=28\\2^x(2+1+\frac{1}{2})=28\\ 2^x(\frac{7}{2})=28\\ 2^x=28(\frac{2}{7})\\ 2^x=8\\x=3$