Question

(N+7)2 binomoo al cuadrado
(
(Y+8)2. (×_5)2. (3×+1)2. (4+1)2

Answer 1

$(N+7)^{2}  = N^{2} + 2(N)(7) + 7^{2}$

[/tex](N+7)^{2}  = N^{2} + 14Y + 49[/tex]

$(Y+8)^{2}  = Y^{2} + 2(Y)(8) + 8^{2}$

$(Y+8)^{2}  = Y^{2} + 16Y + 64$

$(x-5)^{2}  = x^{2} + 2(x)(5) + 5^{2}$

[/tex](x+5)^{2}  = x^{2} + 10x + 25[/tex]

[/tex](3x+1)^{2}  = (3x)^{2} + 2(3x)(1) + 1^{2} [/tex]

[/tex](3x+1)^{2}  = 9x^{2} + 6x + 1[/tex]