Question

Hallar el conjunto solución de las siguientes ecuaciones

Answer 1

Explicación paso a paso:

A)

5(x + 2)² = 45

(x + 2)² = $\frac{45}{5}$

(x + 2)² = 9

$\sqrt{(x + 2)^2} = \sqrt{9}$

x + 2 = 3

x = 1

B)

(x - 1)⁴ - 1 = 80

(x - 1)⁴ = 80 +1

$\sqrt[4]{(x - 1)^4} = \sqrt[4]{81}$

x - 1 = 3

x = 4

C) que paso aqui?

3$\sqrt{10 - 1}$ = 21

3$\sqrt{9}$ = 21

3*3 = 21

9 ≠ 21

D)

$\sqrt[3]{1 - x + 9}$ = 7

$\sqrt[3]{10 - x}$ = 7

$\sqrt[3]{10 - x}$ = 7³

10 - x = 343

-333 = x

E)

5$\sqrt[4]{3x + 1}$ + 3 = 13

5$\sqrt[4]{3x + 1}$ = 10

$\sqrt[4]{3x + 1}$ = $\frac{10}{5}$

$\sqrt[4]{3x + 1}$ = 2

$\sqrt[4]{3x + 1}$⁴ = 2⁴

3x + 1 = 16

3x = 15

x = 5

F)

5x + 7 - 11x + 3 = x - 25

10 - 6x = x - 25

35 = 7x

5 = x

G)

-7x + 1 + 3x - 12 = 7 + 2x

-11 - 4x = 7 + 2x

-18 = 6x

-3 = x

H)

-8 - 5x + 8x = 1 - x + 10

-8 +3x = 11 -x

4x = 19

x = $\frac{19}{4}$

I)

2(x + 3) - 6x = 2(3 -2x)

2x + 6 -6x = 6 -4x

0 = 0

J)

4 - 3(1 - x) + 12 = 5(x + 3)

4 - 3 + 3x + 12 = 5x + 15

13 + 3x = 5x + 15

-2 = 2x

-1 = x