Place the digits
1, 3, 4, 5, 8,
one in each empty cell, so that
the expression is correct.
Y6t
x
P
=
H0u
Respuestas
First, it is better to sort the data vertically.
Y6t x
P
H0u
In these problems what we have to do is play with the multiplication tables, and use our reasoning.
There are 5 letters, and there are 5 numbers so all the letters must be different. so "P" should not be "1", because if it was "1" some letters would be repeated.
and we must also realize that "P" or "Y" should not be "8, 5" "8, 4" "8, 3", because if those two letters were any of these pairs, "H" would be a two-digit number, but that is incorrect. and if those two letters were "8, 1" being P = 8, I'm sure it could not since 8 * 6 = 48, then 8 * t = 2 ?, then t = 3, so that the "2" from "24" to add to 48, and so it would be "50", and we observe that it meets, since it ends in "0", but the 5 that goes to add to the left makes the result "8 + 5 "And that has two digits, so it's impossible since" H "only has one digit, in conclusion" P "should not be equal to" 8 ", nor" 1 ".
what I did, was to use "6", testing which number multiplied by "6" has a response close to "10", so that the "0" is fulfilled.
5 * 6 = 30, but it can not end exactly at "0", since "5 * t" has a result greater than 10, and that would cause it to add to the left, and the "0" would no longer be " 0 "
4 * 6 = 24, is far from finishing the "0"
3 * 6 = 18, I think this would be, have tried to solve the problem with "P" equal to "3". if "P = 3" were true, then the only possibility of the "t" would be "8". since 3 * 8 = 24, and the two would happen to add to the left, to the 18, and thus it would end in 0, and it would be fulfilled. then "u" would be equal to "4". the only possibility of the "Y" would be "1" since 3 * 5 = 15, a 2-digit number. then "H" would be equal to 5.
and everything agrees.
Y6t x
3
H0u
===============
Y68 x
3
H0u
===============
Y68 x
3
H04
===============
168 x
3
H04
===============
168 x
3
504
P=3
P=3H=5
P=3H=5Y=1
P=3H=5Y=1t=8
P=3H=5Y=1t=8u=4
===============
Explicación en español:
porque yo hablo español... :y
primero, es mejor ordenar los datos en forma vertical.
Y6t x
P
H0u
en estos problemas lo que debemos hacer es jugar con las tablas de multiplicar, y utilizar nuestro razonamiento.
hay 5 letras, y hay 5 números asi que todas las letras deben ser diferentes. asi que "P" no debe ser "1", ya que si fuera "1" algunas letras se repetirían.
y también debemos darnos cuenta de que "P" o "Y" no deben valer "8,5" "8,4" "8,3", ya que si esas dos letras fueran alguno de estos pares, "H" seria un numero de dos dígitos, pero eso es incorrecto. y si esas dos letras fueran "8,1" siendo P=8, estoy seguro de que no se podría ya que 8*6=48, entonces 8*t=2?, entonces t=3, para que el "2" del "24" pase a sumar a los 48, y asi seria "50", y observamos que cumple, ya que termina en "0", pero el 5 que pasa a sumar a la izquierda hace que el resultado sea "8+5" y eso tiene dos dígitos, asi que es imposible ya que "H" solo tiene un dígito, en conclusión "P" no debe ser igual a "8", ni "1".
lo que hice, fue utilizar al "6", probando cual numero multiplicado por "6" tenga una respuesta cercana a "10", para que asi se cumpla el "0".
5*6=30, pero no puede terminar exactamente en "0", ya que "5*t" tiene un resultado mayor a 10, y eso haría que pase a sumar a la izquierda, y el "0" ya no seria "0"
4*6=24, esta muy lejos de terminar el "0"
3*6=18, creo que este si seria, haber probemos resolver el problema siendo "P" igual a "3". si "P=3" fuera verdadero, entonces la única posibilidad de la "t" seria "8". ya que 3*8=24, y el dos pasaría a sumar a la izquierda, al 18, y asi terminaría en 0, y se cumpliría. entonces "u" seria igual a "4". la única posibilidad de la "Y" seria "1" ya que 3*5=15, un numero de 2 dígitos. entonces "H" seria igual a 5.
y todo concuerda.
Y6t x
3
H0u
===============
Y68 x
3
H0u
===============
Y68 x
3
H04
===============
168 x
3
H04
===============
168 x
3
504
===============