Question

como resolver las siguientes sistemas de ecuaciones lineales
2x + 5y =1
3x - 1y =10

2x - 2y =2
6x - 5y =1

3x - 4y =6
5x + 9y =10

Answer 1

2x + 5y = 1
3x - 1y = 10
y=(1-2x)/5
3x-(1-2x)/5=10
5(3x) - 1(1) + 1(2x) = 5(10)
15x - 1 + 2x = 50
17x = 50 +1
17x=51
x=51/17
x=3
y=(1-2(3))/5
y= (1 - 6)/5
y=-5/5
y=-1
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2x-2y=2
6x-5y=1
x=(2+2y)/2
6((2+2y)/2)-5y=1
(12+12y)/2-5y=1
1(12)+1(12y)-2(5y)=2(1)
12+12y-10y=2
2y=2-12
y=-10/2
y=-5
x=(2+2(-5))/2
x=(2-10)/2
x=-8/2
x=-4
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3x-4y=6
5x+9y=10
x=(6+4y)/3
5((6+4y)/3)+9y=10
(30+20y)/3+9y=10
1(30)+1(20y)+3(9y)=3(10)
30+20y+27y=30
47y=30-30
47y=0
y=0/47
y=0
x=(6+4(0))/3
x=(6+0)/3
x=6/3
x=2