Question

$\frac{(3x-1)^{2} }{3} =(3x+1)(x+2)$

Answer 1

$\frac{(3x-1)^{2} }{3} =(3x+1)(x+2)\\\\(3x-1)^{2} =((3x+1)(x+2))3\\\\(3x-1)(3x-1)=(3x^{2} +6x+x+2)3\\\\9x^{2} -3x-3x+1=(3x^{2} +7x+2)3\\\\9x^{2} -6x+1=9x^{2} +21x+6\\\\-6x+1=21x+6\\\\1-6=21x+6x\\\\-5=27x\\\\x=-\frac{5}{27}$