ayuda
(2a+3b+c)+5a+8b+c)=
(3a-6b+2c)-(4a+8b)=
-4a-6b)+(-3a-5b-2c)=

Respuestas

Respuesta dada por: goyitopio
4
(2a+3b+c) + ( 5a + 8b + c) = 7a +11b + 2c
2a+5a = 7a
3b+8b = 11b
c+c = 2c
(3a -6b +2c)-( 4a+ 8b) = -a -14b +2c
3a - 4a = - a
-6b -8b= -14b
(-4a-6b) + (-3a -5b -2c) = -7a -11b -2c
-4a -3a = -7a
-6b - 5b = -11b
Preguntas similares