Question

3x+[2y+(3x+y)-(2x+y)]-(x+3y)
ayudaaaaaa, por favor es urgente. :c

Answer 1

Respuesta:

y = -6

x = -2

Explicación paso a paso:

3x+[2y+(3x+y)-(2x+y)]-(x+3y)

3x+[2y+3x+y-2x-y]-(x+3y)

3x+[2y+x]-(x+3y)

3x+2y+x-x-3y

3x-1y

3x = y

x = $\frac{y}{3}$

-y = 3x

y = -3x

............

y = -3x

y = -3* ($\frac{y}{3}$)

3y = -3y

3y + 3y = 0

6y = 0

y = -6

............................

x = $\frac{y}{3}$

x = $\frac{-6}{3}$

x = -2

Answer 2

3x+[2y+3x+y-2x-y]-x-3y
3x + 2y +3x+ y - 2x -y -x -3y
(3+3-2-1)x = 3x
(2+1-1-3)y = -y
3x - y