Question

Me podrías explicar cómo resolver estas integrales?

Answer 1

se utiliza la forma de:
[integral ] x^n dx = x^(n+1)/ n+1
Entonces:
1)
[integral] x^6dx = x^(6+1)/6+1 = x^(7)/7
2)
[integral] x^3dx = x^(3+1)/3+1 = x^(4)/4
3)
[integral] x^8dx =x^(8+1)/8+1= x^(9)/9
4)
[integral]x^11dx= x^(11+1)/11+1= x^(12)/12