Question

a)5+(28-16)+[11-4]=
b)7+35-16+5×[4×(16-11)]=
c)7×[4×(124-111)]=
d)2×[75-4×(128-110)]=
e)5-{[(2×6)+10]-(4×2)}=
f)3×(5-1)+8×[(3-2)×4]=
g)[4-(1×2)]³+[5×(3-2)]÷5=
h)5×[(4+3)×2]+(10-7)=
i)12+(5×3)+1×8=
j)42-[8÷(2×2)]+7=
k)8÷(4-2)8-(15+1)=

Answer 1

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