Question

Resolver las ecuaciones con su comprobacion:

a) x-[ {2+-(3x-1)] }=2-x

b) 5x-3 [x-2(2x-1]=-3

Answer 1

a) x-[{2+(-3x+1)}]=2-x
x-[{2-3x+1}]=2-x
x-(-3x+3)=2-x
x+3x-3=2-x
4x-3=2-x
4x+x=2+3
5x=5
x=5÷5=1

b)5x-3[x-2(2x-1)]=-3
5x-3(x-4x+2)=-3
5x+9x-6=-3
14x=-3+6
14x=3
x=3/14

Answer 2

a) x-[ {2+-(3x-1)] }=2-x

x - (2 - 3x +1) = 2 - x

x - 2 + 3x - 1 = 2 -x

4x - 3 = 2 - x

4x + x = 2+3

5x = 5

x= 1

Verificación:

x-[ {2+-(3x-1)] }=2-x

1 -[ {2+-(3.1-1)] }=2-1

1 - (2 - 2) = 1

1=1

b) 5x-3 [x-2(2x-1]=-3

5x - 3(x - 4x + 2) = -3

5x -3x + 12x - 6 = -3

14x = -3+6

x= 3/14

Verificación:

5x-3 [x-2(2x-1]=-3

$5.\frac{3}{14} - 3 [\frac{3}{14} - 2(2.\frac{3}{14} -1)}= -3$

$\frac{15}{14} -3 [\frac{3}{14} - 2(\frac{6}{14} -1)}= -3$

$\frac{15}{14} - 3 [\frac{3}{14} - 2(-\frac{4}{7})= -3$

$\frac{15}{14} - 3 (\frac{3}{14} +\frac{8}{7} )= -3$

$\frac{15}{14} - 3 . \frac{19}{14} = -3$

$\frac{15}{14} - \frac{57}{14} = -3$

-3 = -3