Question

Resuelve los polinomios Si x=1/2 y= menos 1/3 y z= 3/4

x+(y×z)^1

(x÷y)-(x÷z)

x+ [(y+1/3)^1×z]

Answer 1

1. x+(y×z)^1

$\frac{1}{2} -\frac{1}{3} *\frac{3}{4}$

$\frac{1}{2} -\frac{1}{4}$

$\frac{1}{4}$

2. (x÷y)-(x÷z)

$(-\frac{1}{2} *3)-(\frac{1}{2} *\frac{4}{3} )$

$(-\frac{3}{2} )-\frac{2}{3}$

$-\frac{3}{2} -\frac{2}{3}$

$-\frac{13}{6}$

3. x+ [(y+1/3)^1×z]

$\frac{1}{2} +((-\frac{1}{3} +\frac{1}{3}) *\frac{3}{4})$

$\frac{1}{2} +(0*\frac{3}{4} )$

$\frac{1}{2} + 0$

$\frac{1}{2}$