Question

Reparte 35 en partes inversamente proporcionales a los numeros 4 y 7

Answer 1

sea

sea a y b las dos partes

a = (k) .1/4 = k/4

b = (k).1/7 = k/7

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las dos partes suman 35

k/4 + k/7= 35

7k + 4k /28 = 35

11k/28 = 35

k = 35.28/11

k = 980/11

las partes son

a  = k/4 => (980/11)/4 = 245/11

b = k/7 =>  (980/11)/7 = 140/11