Question

x2-x-56=0
son 2 respuestas

Answer 1

se realiza con la fórmula general x= (-b(+-)√(b^2-4ac))/2a

a=1      b= -1    c= -56

sustituyendo:

x1= [(-1)+√(-1)^2-4(1)(-56)]/2(1)

x1= [-1 + √(1-224)]/2

x1= [ -1 + √223]/2

x1= [ -1 + 14.93]/2

x1 = 13.93/2

x1= 6.965

x2= [(-1) - √(-1)^2-4(1)(-56)]/2(1)

x2= [-1 - √(1-224)]/2

x2= [ -1 - √223]/2

x2= [ -1 - 14.93]/2

x2 =  -15.93/2

x2=  -7.965