calcular las masas de H2O,yO2 con la siguiente ecuacion equilibrada 2C4H10+13O2----------------8CO2+3H2O si contamos con 150gr de butano ( C4H10)
Respuestas
2C4H10 + 13O2 → 8CO2 + 3H2O
Mm C4H10 = 58 g/mol
H2O = 18 g/mol
O2 = 32 g/mol
a. calcular gramos de H2O
g H2O = 150 g C4H10 x 1 mol C4H1O x 3 mol H2O x 18 g H2O
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58 g C4H10 2 mol C4H10 1 mol H2O
g H2O = 69.83
b. calcular gramos de O2
g O2 = 150 g C4H10 x 1 mol C4H1O x 13 mol O2 x 32 g O2
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58 g C4H10 2 mol C4H10 1 mol H2O
g O2 = 537.93