Respuestas
comensemos:
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sen (x+20) . cosec ( 80-2x)= 1
sen(x+20) . 1 = 1
sen(80-2x)
sen(x+20) = sen(80-2x)
x+20=80-2x
3x=60
x=20
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sen ( 3x-20) . cosec ( x +20) =1
sen(3x-20) . 1 = 1
sen(x+20)
sen(3x-20) = sen(x+20)
3x-20=x+20
2x=40
x=20
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cos (7x-3) . sec ( 5x+7) =1
cos(7x-3) . 1 = 1
cos(5x+7)
sen(7x-3) = sen(5x+7)
7x-3=5x+7
2x=10
x=5
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cos (8x-10) . sec (70) =1
cos(8x-10) . 1 = 1
cos(70)
sen(8x-10) = sen(70)
8x-10=70
8x=80
x=10
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tan( x-30) . cot ( 2x-40) =1
tan(x-30) . 1 = 1
tan(2x-40)
tan(x-30) = tan(2x-40)
x-30=2x-40
x=10
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un gusto....=D