Question

Por fa √3cot20-4cos20

Answer 1

= √3*cos 20/sin 20 - 4*cos 20

= (√3*cos 20 - 4*cos 20*sin 20)//sin 20

= (√3*cos 20 - 2*2*cos 20*sin 20)//sin 20

= {√3*cos 20 - 2*sin (2*20)}//sin 20

= {√3*cos 20 - 2*sin 40}//sin 20 {since sin 2x = 2*sin x*cosx}

= {2*sin 60*cos 20 - 2*sin 40}//sin 20 {since sin 60 = √3/2}