Question

Cuantos gramos de acido sulfurico se necesita para obtener 4 litros de solucion 2 molar

Answer 1

Mm H2SO4 = 98 g/mol

.01 calcular moles despejando de la fórmula de molaridad

M = n /V(L)

n = M x V(L)

n = 4 L  x  2 mol/L

n = 8 moles

2. calcular gramos aplicando la fórmula

n = masa/Mm

masa = n x Mm

masa = 8 mol x 98 g/mol

masa = 784 g de H2SO4

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otra forma

M = g soluto / (Mm  X  V(L) )

g = M x Mm x V(L)

g = 2 mol/L  x 4 L x 98 g/mol

g = 784 de H2SO4