Question

Método de igualación. *9x+16y=7.
* 4y-3x=0

Answer 1

x=(7-16y)/9

x=4y/3

(7-16y)/9=4y/3

21-48y=36y

36y+48y=21

84y=21

y=21/84=1/4

x=(4/4)/3=1/3

x=1/3, y=1/4

Answer 2

9x+16y=7

9x=-16y+7

x =-16y+7 / 9

_____________________

4y-3x=0

(-1) -3y= -4y

3x=4y

x= 4y / 3

____________

-16y+7/9 =4y /3

3(-16y+7)= 9(4y)

-48y+21= 36y

-48y-36y= -21

-84y= -21

y = -21 / -84

y = 1/4

remplazamos y

4y-3x=0

4(1/4) -3x=0

1 -3x= 0

-3x= -1

x=1/3

prueba

9x+16y=7

9(1/3)+16(1/4) =7

3+4=7

7=7            R// SI ES CONSISTEENTE (1/3; 1/4)