Question

Me ayudan con este calculo porfavor

Answer 1

Solucion.

Resolvamos las operaciones paso a pasito y nos queda:

$\sqrt{\frac{3}{4}-\frac{2}{5}}=\sqrt{\frac{15-8}{20}}=\sqrt{\frac{7}{20}}\\\frac{\sqrt{7}}{\sqrt{20}}=\frac{\sqrt{7}}{2\sqrt{5}}\\\frac{\sqrt{7}}{2\sqrt{5}}\div\frac{2}{5}=\frac{35}{4\sqrt{5}}\\(1-\frac{3}{5})^{-2}=(\frac{2}{5})^{-2}=\frac{1}{(\frac{2}{5})^{2}}=\frac{1}{\frac{4}{25}}=\frac{25}{4}$

Finalmente reuniendo todas las operaciones nos queda:

$\frac{35}{4\sqrt{5}}-\frac{25}{4}+\frac{1}{4}=\frac{35}{4\sqrt{5}}-\frac{26}{4}\\\frac{(4)(35)-(4\sqrt{5})(26)}{16\sqrt{5}}=\frac{140-104\sqrt{5}}{16\sqrt{5}}\\\frac{140}{16\sqrt{5}}-\frac{104\sqrt{5}}{16\sqrt{5}}=\frac{35}{4\sqrt{5}}-\frac{13}{2\sqrt{5}}$

Saludos.