Question

URGENTE!!!!
Dado P(x)= 4x3+ 2x2+x Q(x) = x3+ 2x2+x. calcule P(x)-Q(x); si x =2

Answer 1

$p(x) = 4 {x}^{3} + 2 {x}^{2} + x \\ q(x) = {x}^{3} + 2 {x}^{2} + x \\ \\ p(x) - q(x) = 4 {x}^{3} + 2 {x}^{2} + x - ( {x}^{3} + 2 {x}^{2} + x) \\p(x) - q(x) = 4 {x}^{3} + 2 {x}^{2} + x - {x}^{3} - 2 {x}^{2} - x \\ p(x) - q(x) = 3 {x}^{3} \\ \\ si \: x = 2 \\ \\ p(2) - q(2) = 3 \times {2}^{3} \\ p(2) - q(2) = 3 \times 8 \\ p(2) - q(2) = 24$