Question

Ayuda nevesito resolver esto
El tema es "productos notables" por favor agradezco su ayuda

Answer 1

1)$(x+5)^{3}$=$x^{3}+125+3(x)(5)(x+5)$

=$x^{3}+125+15x(x+5)$

=$x^{3}+125+15x^{2}+75x$

2)$(y-4)^{3}=y^{3}-64-3(y)(4)(y-4)$

=$y^{3}-64-12y(y-4)$

=$y^{3}-64-12y^{2} +48$

3)$(x+2)^{3}=x^{3}+8+3(x)(2)(x+2)$

=$x^{3}+8+6x(x+2)$

=$x^{3}+8+6x^{2}+12x$

4)$(2y-5)^{3}=[tex] 8y^{3}-125-3(2y)(5)(2y-5)$

=$8y^{3}-125-30y(2y-5)$

=$8y^{3}-125-60y^{2}+150y$

5)$(3x+y)^{3}=27x^{3}+y^{3}+3(3x)(y)(3x+y)$

=$27x^{3}+y^{3}+9xy(3x+y)$

=$27x^{3}+y^{3}+27x^{2}y+9xy^{2}$

6)$(2y-3y)^{3}=(-y)^{3}=-y^{3}$

7)$(2x+1)^{3}=8x^{3}+1+3(2x)(1)(2x+1)$

=$8x^{3}+1+6x(2x+1)$

=$8x^{3}+1+12x^{2} +6x$

8)$(2y-1)^{3}=8y^{3}-1-3(2y)(1)(2y-1)$

=$8y^{3}-1-6y(2y-1)$

=

9)($4x^{2}+2y^{2}$)³=$64^{6}+8y^{3}+3(4x^{2})(2y)(4x^{2}+2y)$

=$64x^{6}+8y^{3}+24x^{2}y(4x^{2}+2y)$

=$64x^{6}+8y^{3}+96x^{4}y +48x^{2}y^{2}$