Question

Por Favor !!

Answer 1

a)
7x + 3x ≤ 2(x + 4)
10x ≤ 2x + 8
8x ≤ 8
x ≤ 1
Entonces x ∈ <-∞ , 1]

b)
-3(x + 2) ≥ 2x - 1
-3x - 6 ≥ 2x - 1
-5x ≥ 5
5x ≤ -5
x ≤ -1
Entonces x ∈ <-∞ , -1]

c)
(-12x + 6) : 6 < 2(x - 6) - 3
[6(-2x + 1) : 6] < 2x - 12 - 3
-2x + 1 < 2x -15
-4x < -16
4x > 16
x > 4
Entonces x ∈ <4 , +∞>

d)
2x (x+3) - 1 > 2x² ⁺ 5
2x² ⁺ 6x - 1 > 2x² ⁺ 5
6x > 6
x > 1
Entonces x ∈ <1 , +∞>